maths a level students come

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#1
bl4z31ng
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(edexcel)

wtf was that paper

started out pretty reasonable then turned into absolute bullshitmaxxing

#2
Galactc
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Easiest paper of my life but also why was there so much integration

#4
bl4z31ng
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if you found it easy then you are an absolute fucking genius. even the a* students found it difficult

#6
Castawaytwizz
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yeah id like to know what "easy" means, I got 95/100 on my last mock and I think I might have barely broken ~80 on this one

#7
Galactc
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I'm usually quite good at getting like 55% so if the boundaries are lower this year that's good for me I thought question 1-9 were free

#13
Castawaytwizz
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To be honest I thought questions 7/9 were some of the most difficult mid-paper questions they've ever released, and then the last 4/5 questions were also more difficult than normal

#15
Galactc
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Tbf my teachers held a maths revision thing right before and since I need a B I've been nonstop revising for the past 3 weeks so maybe I'm just more locked in than usual and the paper actually was really hard

#16
Castawaytwizz
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Fair play, congrats man

#18
Galactc
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Nah I'm going to open the envelope on results day and get a D atp if literally everyone else found it hard it's so cooked 😭

#14
bl4z31ng
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yeah the first few questions were somewhat reasonable except the circle one then you had the geometric series question, the proof question and the last differentiation question just to name a few

#17
Galactc
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The question about kcot2x was bs I'm convinced k was not an integer 😭

#21
Castawaytwizz
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I got 2 for that one,

I flipped the "tan(a+b)" formula to get (1-tan^2x)/(2tanx)

then you expand the equation it gives you to get cotx - tanx which becomes (cos^2x - sin^2x)/(sinxcosx) -> (1-2sin^2x)/(sinxcosx)

you derive 1 + tan^2x = sec^2x, so you know that 1 - tan^2x = sec^2x - 2tan^2x

which becomes (1-2sin^2x)/(cos^2x)

therefore, cot2x is equal to (1-2sin^2x)/(cos^2x)(2tanx)

which is equal to (1-2sin^2x)(cosx)/(cos^2x)(sinx), so (1-2sin^2x)/(cosx)(2sinx)

which is exactly one half of the expansion above, so therefore k is 2

#20
Castawaytwizz
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Geometric series one you're supposed to equal term4/term3 = term5/term4 to find theta=pi/6, then sub that into term4/term3 to get root6 as the ratio, then sub pi/6 into the third term and divide it by root6 twice to find term1/2, then add term1/2/3 together. Not a clue how you do part c) of the Algebraic integration one though, I got stuck in an infinite integration by parts loop

#3
Castawaytwizz
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Unironically hardest paper I've ever seen, thought they accidentally gave me a Further paper or something. Don't think I did too badly, but objectively those questions are more difficult than all the past papers, so silver lining the grade boundaries should fall.

#5
W1ngFly
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Send me the paper link pls

#8
Castawaytwizz
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Not released yet, will probably be on Tiktok tomorrow

#10
W1ngFly
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Haha Tiktok, right...

#9
bl4z31ng
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bruh I can’t it happened less than 5 hours ago, british exam boards release the exam paper publicly a year after it took place

#12
Galactc
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Come back here in like September and maybe I can give it to you

#19
W1ngFly
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Ok hopefullly it's out b4 Jan 2027, maybe I can have a go at it

#11
xv108
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i give it next year am i cooked

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