(edexcel)
wtf was that paper
started out pretty reasonable then turned into absolute bullshitmaxxing
maths a level students come
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Unironically hardest paper I've ever seen, thought they accidentally gave me a Further paper or something. Don't think I did too badly, but objectively those questions are more difficult than all the past papers, so silver lining the grade boundaries should fall.
Galactc [#2]Easiest paper of my life but also why was there so much integration
if you found it easy then you are an absolute fucking genius. even the a* students found it difficult
bl4z31ng [#4]if you found it easy then you are an absolute fucking genius. even the a* students found it difficult
yeah id like to know what "easy" means, I got 95/100 on my last mock and I think I might have barely broken ~80 on this one
bl4z31ng [#4]if you found it easy then you are an absolute fucking genius. even the a* students found it difficult
I'm usually quite good at getting like 55% so if the boundaries are lower this year that's good for me I thought question 1-9 were free
W1ngFly [#5]Send me the paper link pls
Not released yet, will probably be on Tiktok tomorrow
W1ngFly [#5]Send me the paper link pls
bruh I can’t it happened less than 5 hours ago, british exam boards release the exam paper publicly a year after it took place
Castawaytwizz [#8]Not released yet, will probably be on Tiktok tomorrow
Haha Tiktok, right...
W1ngFly [#5]Send me the paper link pls
Come back here in like September and maybe I can give it to you
Galactc [#7]I'm usually quite good at getting like 55% so if the boundaries are lower this year that's good for me I thought question 1-9 were free
To be honest I thought questions 7/9 were some of the most difficult mid-paper questions they've ever released, and then the last 4/5 questions were also more difficult than normal
Galactc [#7]I'm usually quite good at getting like 55% so if the boundaries are lower this year that's good for me I thought question 1-9 were free
yeah the first few questions were somewhat reasonable except the circle one then you had the geometric series question, the proof question and the last differentiation question just to name a few
Castawaytwizz [#13]To be honest I thought questions 7/9 were some of the most difficult mid-paper questions they've ever released, and then the last 4/5 questions were also more difficult than normal
Tbf my teachers held a maths revision thing right before and since I need a B I've been nonstop revising for the past 3 weeks so maybe I'm just more locked in than usual and the paper actually was really hard
Galactc [#15]Tbf my teachers held a maths revision thing right before and since I need a B I've been nonstop revising for the past 3 weeks so maybe I'm just more locked in than usual and the paper actually was really hard
Fair play, congrats man
bl4z31ng [#14]yeah the first few questions were somewhat reasonable except the circle one then you had the geometric series question, the proof question and the last differentiation question just to name a few
The question about kcot2x was bs I'm convinced k was not an integer 😭
Castawaytwizz [#16]Fair play, congrats man
Nah I'm going to open the envelope on results day and get a D atp if literally everyone else found it hard it's so cooked 😭
Galactc [#12]Come back here in like September and maybe I can give it to you
Ok hopefullly it's out b4 Jan 2027, maybe I can have a go at it
bl4z31ng [#14]yeah the first few questions were somewhat reasonable except the circle one then you had the geometric series question, the proof question and the last differentiation question just to name a few
Geometric series one you're supposed to equal term4/term3 = term5/term4 to find theta=pi/6, then sub that into term4/term3 to get root6 as the ratio, then sub pi/6 into the third term and divide it by root6 twice to find term1/2, then add term1/2/3 together. Not a clue how you do part c) of the Algebraic integration one though, I got stuck in an infinite integration by parts loop
Galactc [#17]The question about kcot2x was bs I'm convinced k was not an integer 😭
I got 2 for that one,
I flipped the "tan(a+b)" formula to get (1-tan^2x)/(2tanx)
then you expand the equation it gives you to get cotx - tanx which becomes (cos^2x - sin^2x)/(sinxcosx) -> (1-2sin^2x)/(sinxcosx)
you derive 1 + tan^2x = sec^2x, so you know that 1 - tan^2x = sec^2x - 2tan^2x
which becomes (1-2sin^2x)/(cos^2x)
therefore, cot2x is equal to (1-2sin^2x)/(cos^2x)(2tanx)
which is equal to (1-2sin^2x)(cosx)/(cos^2x)(sinx), so (1-2sin^2x)/(cosx)(2sinx)
which is exactly one half of the expansion above, so therefore k is 2
Discord