mathematics knowers come

what is the name of this shit? i need to make a code in C to solve this but idk wtf this is
https://i.imgur.com/3xkM2YN.png
EDIT: thanks for the answers :D

what part dont u know

explain in val terms when you get the answer

all i know there is the sigma but I don't wanna go back to knowing math so I will not help you

thats pythagorean theorem

thats an awful lot of symbols :/

it's a summision sign when there is a sign like that that means everything inside is added If you are talking about the symbol

Sigma indicates summation, the lower value indicates the starting point and the upper value indications the upper bound. So you take the sum of the function inside the [ ] brackets for the values specified by Sigma.

that symbol is sum and for the first one i=1 and the top is 6. so u have u have sub in the numbers 1 to 6 individually where the i's are in the formula and then 2,3 and so on, then add them up. that's the long version think there's an easier version but i forgot prolly

somatorio de funcoes trigonometricas. O indice i varia de 1 a 6 no primeiro exemplo.
Basicamente para cada i que voce varia voce tem que substituir na funçao e tera um resultado. Faça o mesmo processo até o numero 6 e some tudo.
nos outros exemplos é apenas aplicação do mesmo somatorio na função. Não gosto de usar o i como indice pois pode confundir com números complexos(que pode ser desmembrado em seno e cosseno).ex: Simbolo de somatorio (x+1) com subindice de 1 a 3. O resultado seria res: (1+1)+(2+1)+(3+1)= 9
é mais simples do que parece.

The big greek E is a denotation for sum.

As i=1 is at the bottom and 6 at the top you are basically summing the equation right of it for i=1,2,3... till 6 same goes on for the other examples with different substiutions for k and j according to your notation ( if this brief explanation is not clear enough check out a khan acadmey vid on sigma notation)

the "e" is Eulers number i.e. the base of a natural logarithm

I assume "sen" is just the sine in a different notation (you should know it from trignometry)

thanks for the answers :D

Think of each sigma as a for loop where what is under the sigma is where the loop starts and what is on top is where the loop ends

I'm assuming it's simple summation. On the bottom is a i = a number. that is the number you start with. On top of the sigma symbol is another number. that is the number you end with. Plug in the number you start with (this case it is i = 1) into the equation, and after simplifying, you get a number. Now continue plugging in integers starting from i = 1 until you reach the number on top. You should have a new number every time you plug in a new integer. now add all your answers up and you get the sum.

So for the first problem plug in i = 1 into i^2i+e^i * isin(2i). you have a number. next plug in i = 2. you will have a new number. keep doing that until you reach i = 6 where you have 6 different numbers. add them together.

The last problem you have to do this twice because you have two variables. Do the summation for the innermost ones and then you should have a bunch of different terms added together with the variable i. Do the same thing with the outer summation.