58 -> 377

34 -> 183

27 -> 106

62 -> 461

83 -> ?

someone find the number pls

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58 -> 377

34 -> 183

27 -> 106

62 -> 461

83 -> ?

I will refer to the left number as X and right as Y

1) ones digit

X's ones digit is 1 larger than Y's ones digit (8-1 = 7, 4-1 = 3 and on)

so for 83, it will be 2 --> ??2

fairly straightforward

2) tens digit

first X's tens digit(5) + first Y's tens digit(3) = 8, thus 34 --> 1**8**3

5+3+2 = 10, 1**0**6 and on

so for 83, it will be 5+3+2+6+ 8 = 24, ?42

3) hundreds digit

genearlly, Y's hundreds digit is 2 less than X's.

but we see an exception: 27 --> 106

if we go back to how we got the tens digit, it was 5+3+2, 10. here, we only used the 0 for our solution, and dumped 1. I though that 1 back there should come back here, making it 2-2+1 = 1, 27 --> 106

so for 83, it should be 8-2 = 6, but remember, we dumped the 2 from 24 in tens digit, so 6+2 =8

THEREFORE, ANSWER = 842

Now, there are some faulty reasoning in my solution

- my solution fails to explain the 7 in tens digit for 58 --> 377. i just said that the first value was given a random number
- My solution only works if the order matters; for most of these problems, order often doesn't account for the answer, but that was the only way i saw the answer
- the number becomes invalid if ones digit is 0 , because 0-1 = -1, we can't have that. similar errors could occur with hundreds digit

BUT, for the given numbers, i didn't come across any error solutions, so i speculate im right? maybe idk

It doesn't follow a linear pattern exactly (nor does it seem to fit other basic curves) which is what I would expect from the whole numbers -> y = 9.4547x - 146.08 with a R^2 of R² = 0.986.

This means 83 would be 638.66 which isn't a whole number either.

I would guess there is some hidden arithmetic equation at play. potentially based on the order of the numbers you gave