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2 + 2 = 5

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#1
Monsteiur

Can someone prove this

#2
Itsover
4
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OK Ardis log off your alt

#3
Skyns
0
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2+2=5

#4
archetype
0
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2 + 2 = 5

say a = 2 and b = 2
a + b = 5
(a + b) × (a - b) = 5 × (a - b)
(a + b) (a - b) ÷ (a - b) = 5 (a - b) ÷ (a - b)
a + b = 5
2 + 2 = 5

find the trick? ;D

#5
911dot
3
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It is wrong from before the 1st step tho.

#9
archetype
0
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i edited it for clarification

#12
911dot
0
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I already said itt tho it is wrong before the 1st step since if you divide with 0 it becomes undefined.

Edit: Also you can do 0/12 and it equals to zero but if you do 12/0 = It becomes undefined.

#13
archetype
1
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sportsman beat u to it with a more concise reply...have a half eaten cookie 🍪:(

#15
911dot
0
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Thanks for the cookie also I was slow af for no reason idk why. I usually multiply or find the mistake quickly if it is hard tho. (I somehow struggle against easy questsions:)

#18
archetype
0
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everyone approaches math at their own pace no one is expected to be von neumannesque (my math goat)

#24
911dot
0
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Yeah I guess you're right.

#6
sp0rtsman
3
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(trick is that you are not allowed to divide by 0)

#7
archetype
0
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here's a cookie 🍪

#8
sp0rtsman
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yupiee!!!

#14
Uribaba
0
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it is wrong from the first step u r writing a + b = 5 as your first step and u r asssuming a and b 2 so u r basically writing 2+2=5 where is the proof then xd

#10
Uribaba
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"say a = 2 and b = 2
a + b = 5" thats what u r supposed to prove why r u so u cant write a + b = 5

#16
edgno1fan3
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unnecessary conversion from simple constants to confusing variables, bad practice

failure to mention constraints on a and b during the division step, which is ironic since a and b are constants that are unnecessarily encoded for the sole purpose of confusion

division by 0

criminal maths. i sentence you to life without parole.

#17
archetype
0
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nooo not math jail ToT i still have to take linalg and discrete

also here's a cookie 🍪

#11
1One1
0
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1 is one
2 is two
8 is three
5 is four
7 is five
4 is six
9 is seven
3 is eight
6 is nine

So, two + two = four
2 + 2 = 5

It is just how we define the number

#19
viiseryZ
1
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  1. 20 = 20
  2. 16 - 36 = 25 - 45
  3. 16 - 36 + 81/4 = 25 - 45 + 81/4
  4. (4-9/2)² = (5-9/2)²
  5. 4-9/2 = 5-9/2
  6. 4 = 5
  7. 2 + 2 = 5
#21
Uribaba
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how can u say 4-9/2=5-9/2 when clearlynits (-1/2)^2 and (1/2)^2

#22
viiseryZ
1
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Buddy, since 2+2=5 is not true, you have to make a mistake somewhere to prove it, and you need to use absolute value—if you don't, this is the result

#25
Uribaba
0
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ya ik im just pointing out the mistake im positive you know that as well

#20
themaniel
0
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Radiohead reference

#23
mzto
0
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(a) = 2 (float but is showed as an intenger) and (b) is the same. so (a) can be any decimal number (2.x) and (b) can be any decimal number aswell (2.y)
so you can say (a) and (b) belongs to R. there are multiple solutions for this problem. (a) and (b) can be any number from R.

#26
Conceit
0
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That's a fire song

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