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Smart vlr users come pt4

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#1
RickyIndian

https://imgur.com/a/v4uSNeC

is this correct? if not, what should i do?

https://imgur.com/a/Dr9MrmC

how do i do this

sorry mods meant for off topic

#2
CryoZanderDerrekEnjoyer
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i will look into it

#5
CryoZanderDerrekEnjoyer
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First question

DISTANCE: s = 1/2a x t^2 + v0 x t

VELOCITY: s = v^2 - v0^2 / 2a

s stands for distance

part1: 0 - 9.5s

s: 1.5 x 9.5^2
s = 135.375

v: 135.375 = v^2 / 6
v: 812.25 = v^2
v = 28.5
------------------------------------
part2: 9.5s - 11.5s

s: -1.5 x 4 + 28.5 x 2
s = 51

part1 + part2 = 135.375 + 51 = 186.375m

#11
clocksky888
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I'll add the steps for the first question under your reply since ... , just in case 😉

https://i.imgur.com/e4gwBfG.png

#8
CryoZanderDerrekEnjoyer
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Second question

DISTANCE: s = 1/2a x t^2 + v0 x t

VELOCITY: s = v^2 - v0^2 / 2a

GIVEN:

Sue velocity = 33.0m/s
Sue acceleration = -1.90m/s^2
Sue distance into tunnel = 0m

Van velocity = 5.20m/s
Van acceleration = 0m/s^2
Van distance into tunnel = 175m

LOOKING FOR:

distance and time

EQUATION NEEDED: (For a collision to happen, you need to have both vehicles on the same "coordinates". Thats how they collide. So in following question, we just use the basic kinematic equations and set them equal. The question asks how much time is needed. So we solve for t.

Sue_distance = Van_distance

1/2a x t^2 + v0 x t = (1/2a x t^2 + v0 x t) + 175m
-0.95 x t^2 + 33 x t = (5.2 x t) + 175
-0.95t^2 + 33t = 5.2t + 175
-0.95t^2 + 27.8t - 175 = 0

solve quadratic equation: two solutions, you pick the one closer to 0 because thats the earlier/quicker collision

t = 9.16599

Now for distance just use the same basic kinetic formula
s = 1/2a x t^2 + v0 x t

s: -0.95 x 9.16599^2 + 33 x 9.16599
s: -79.81 + 302.477

s = 222.667m

final solutions:

t = 9.16599

s = 222.667m

additional help:
https://www.mathsisfun.com/quadratic-equation-solver.html
https://www.desmos.com/calculator/ysjxt0jazm

lmk if its correct

#12
RickyIndian
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thanks so much bro

spent last 2 days on these things and my teacher loves to not help

im probably gonna ask for more help like this and thanks in advance

#15
333triplethreat
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bro.... just use chatgpt

#16
RickyIndian
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it is wrong 99% of the time for physics

#17
clocksky888
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Use GPT-4 --> Wolfram plug-in

#19
CryoZanderDerrekEnjoyer
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chatgpt is absolutely horrid for maths/physics

this bitch once said 1^2 = 2

#20
333triplethreat
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they arent perfect bro, just ask them to see if they made a mistake and they will spot it. I did that many times and it works

#22
CryoZanderDerrekEnjoyer
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it works but its not 100% reliable

and if youre not very good at the subject you can get confused quite easily

#23
333triplethreat
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yeah i feel u. prob just best to first look at a yt vid then come back tbh.

#25
CryoZanderDerrekEnjoyer
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Khan academy 💯

#26
333triplethreat
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ngl i dont really like u but
education bonds us all :)

#21
CryoZanderDerrekEnjoyer
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all good bro its a pleasure

shoot me a dm whenever u need something

#24
h786
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spent last 2 days on these things and my teacher loves to not help

cherish any help your teacher gives you, because once you get to college they will not care about you, its all about independence and office hours are basically useless unless you use them correctly, time is money in college.

#14
clocksky888
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Same as #11 .... <3

https://i.imgur.com/RNc6x78.png

#27
CryoZanderDerrekEnjoyer
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nice work brotha 🙏 what program do u use for this? i heard someting of LaTeX but i have absolutely no idea about it whatsoever

#29
clocksky888
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Aye, LATEX for which I used a free of charge Overleaf cloud <-- pretty convenient and handy on the go editor.

Now also one word on the solver too... as technically you have the option to use Wolfram's API through GPT-4 by adding Wolfram as a plug-in <-- but in the paid GPT-4 version. The chat GPT part comes just as an interpreter (and pretty f-ing good one as expected) for the solver to break down the wording into algebraic form ... etc.

Regarding capabilities, both Wolfram's Mathematica and Maple were/are pretty good known calculus solvers - I remember using more Mathematica for calc but on occassions would also use Maple for linear algebra (don't recall why I specifically choose Maple over Mathematica for LinAlg though...) too back in the days before GPT. So, they have been known for their ability to get you going, beside Matlab.

Saying I'm incredibly impressed would be an understatement 🤯, as with the above combo, you could get a clear step by step explanations, and If something isn't clear, you have the option to ask for further clarification <-- this was not possible during my times, but HolyyyF... - amazing how it makes self-study so much easier, though not sure how topic of integration would be dealt, and in what details, with said method.

#31
CryoZanderDerrekEnjoyer
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Ight thanks a lot for these useful information bro 🙏🙏🙏 Definetely will help me going

#33
CryoZanderDerrekEnjoyer
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Ive looked into the programs... Jesus christ, 1k+ Dollars for Maple??? Thats absolutely ridiculous.

Guess i will stay with wolfram alpha and khan academy lol...

#34
clocksky888
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hehe... F-it ... you'd be more than fine with just Wolfram... you can get Maple Calc app for your phone if you need but for unlimited steps you'd need a paid subscription which depending on your budget may be okeyish ... but essentially, with khan's or/and other stuff it should be more than enough.

One more thing though, If you're into tutorial vids similar to khan, check out mathtutordvd guy <-- he's pretty good in explaining some of the complicated topics, putting them into easy to grasp scenarios etc.

#9
CribbiterCrab2
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🐐

#10
CryoZanderDerrekEnjoyer
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🙏🙏🙏🙏

#3
Emmy_TOF
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Grade 10 physic can't?
age exposed

#4
mysterii
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his age has been known

#6
CryoZanderDerrekEnjoyer
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rickyindian come ^_^

#7
wizardbot
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Your calculation in the 1st question is probably off. The answer is 186.375, I could send you the soln if you want

#13
SmartPerson
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ez

#18
SEN_FAN335
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ricky my physics goat

#30
terribletyranny
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indian in name and dont know physics = questionable

#32
RickyIndian
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vlr user when he meets someone who asks for school help:

#35
cobalt21312
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drop out

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