TOP 6 HOPIUM

isn't it technically possible for a team with only having one win on the regular season to be in the top 6 and therefore qualify to playoffs?

let's say team A go undefeated and went 9-0, and team B also went undefeated barring their loss to team A. and from team C to team J they only gonna have one win and loss all of their matches, so like team C wins against team D, team D wins against team C, team J wins against team C, and so on.

the final standings would look something like this:

1. Team A: 9-0
2. Team B: 8-1
3. Team C: 1-8
4. Team D: 1-8
5. Team E: 1-8
6. Team F: 1-8
7. Team G: 1-8
8. Team H: 1-8
9. Team I: 1-8
10. Team J: 1-8

with this, the head-to-head tiebreaker for teams ranked 3-10 would be useless cause they all win against one another, with the only thing separating them is how the map/round differential.

I know that this is the most unlikeliest of outcomes, but is this technically possible or am I missing something? (I've spent all my copium on this one)

my questions is: why?

In a hypothetical situation if this does happen it will be based off of rounds wins / kills so even someone from (1-9) score will be above other team with same win like round differential as you say alr

unfortunately this doesn't work as there are 25 wins to 73 losses and they have to be equal