truck driver

This is not a banger
Quick 2-0 Vit

Nt trembo

0/8

Being "THE FIRST VALORANT CHAMPION" is more special, the first page of the book is a historical moment.

retired concent creator

Bro you are currently supporting an ongoing genocide with your taxes.

I have never supported any genocide in my life.

you may have different ways to cover it up but in the end you are the same

you are the same

TH and FUT automatically qualify for the champions

Am I right?

The entire management should resign, and a professional management team like Fut should take their place.

I know you're not used to showing respect. But show some respect to FUT

NA fan watches an EMEA player for the first time

https://x.com/Luinwess/status/1810794486538138020?t=PkxTPtvXc_M4XHxpL2pvhA&s=19

this guy says

1. wins
2. h2h

Thank God Navi didn't get wo0t

Leviatan is a good team but yes it is a bit overrated

grubinho and sheydos seem unlucky

FUT is a good team to lose to

bro had to wait 3 months to write this 💀

bottom team flair detected opinion rejected

Easy money

You keep saying the same things. Lev is smurfing Americas and then loses to FUT. They go back home and continue smurfing Americas from where they left off.

Your opinion = 💩

Demon1 above Alfajer is a crime

Karmine corp

They scored 3 points with a completely lucky run and now have almost the same points as FUT.
I hope TH, Fut, Fnatic, and Vitality make it to the Champions

The only thing I remember is cryo's life game :)

AIM

1. Mrfalin
2. Saadhak
3. Boo
4. Laz
5. Pigstio

MECHANICS

1. Saadhak
2. Mrfalin
3. Boo
4. Laz
5. Pigstio

CALLING

1. Boo
2. Mrfalin
3. Saadhak
4. Laz
5. Pigstio

Bro said navi 💀

2/8

cringe sen fans are crying because there is no z0kk0n

Disband

we don't understand either

I'm just waiting for thousands of people to make that symbol in the next match

he wasn't offensive. he was just making the Turkish symbol

Fuck UEFA 🖕

good jinx attempt

0/8

Riens
nicest guy in valorant

Riens

0/8

thanos is back

There is no team called "impossible task"

He is 3x better than redgar

Most teams may think that Turkish players are undisciplined, or they may think that the language barrier will be a big problem, things like that in general.

Turkish T1 is doing well thanks to FUT

I think more teams will sign Turkish players when the season ends. There is a prejudice against Turkish players in most teams, but I believe we have been breaking this recently.

real pig exposed 🐷

everything can change
but prism operator💀

I don't think it looks right either
gives different answers every time

I asked

To solve this problem, we'll follow these steps:

1. Find the derivative of ( f(x) ).
2. Determine the values of ( p ) and ( q ) where the tangent line is the same at both points.
3. Use the derivative to find the slope of the tangent line.
4. Use the points and the slope to find the equation of the tangent line.

Given:
[ f(x) = x^4 + 2x^3 - 11x^2 - 13x + 35 ]

1. Calculate the derivative ( f'(x) ):
   [ f'(x) = 4x^3 + 6x^2 - 22x - 13 ]

2. Set the derivative equal to zero to find the critical points (which might be our ( p ) and ( q )):
   [ 4x^3 + 6x^2 - 22x - 13 = 0 ]

Let's solve this cubic equation to find the roots ( p ) and ( q ). This can be done using numerical methods or by solving it analytically. For the sake of simplicity, we will use a symbolic approach to find the exact roots.

from sympy import symbols, solve

x = symbols('x')
f_prime = 4*x**3 + 6*x**2 - 22*x - 13
roots = solve(f_prime, x)
roots

Running this in a Python environment with symbolic computation capabilities (like SymPy) will give us the roots.

3. Suppose we find the roots to be ( p ) and ( q ). These are the ( x )-values where the tangent line is the same. Now we need to find the slope of the tangent line at these points. The slope ( m ) is given by ( f'(p) ).

4. Find the equation of the tangent line. Using the point-slope form of the line equation:
   [ y - f(p) = m(x - p) ]
   where ( m = f'(p) ).

Since the tangent line is the same at both ( x = p ) and ( x = q ), it implies that ( f'(p) = f'(q) = m ).

Finally, let’s find the roots and the equation of the tangent line step by step.

Step-by-Step Solution:

1. Derivative:
   [ f'(x) = 4x^3 + 6x^2 - 22x - 13 ]

2. Find roots ( p ) and ( q ):
   Solve ( 4x^3 + 6x^2 - 22x - 13 = 0 ).

3. Evaluate ( f(p) ) and ( f(q) ):
   [ f(p) = p^4 + 2p^3 - 11p^2 - 13p + 35 ]
   [ f(q) = q^4 + 2q^3 - 11q^2 - 13q + 35 ]

4. Find the slope ( m ):
   [ m = f'(p) = f'(q) ]

5. Equation of the tangent line:
   Using the point ( (p, f(p)) ):
   [ y - f(p) = m(x - p) ]

Finding the Roots

Let's use a symbolic solver to find the roots of ( f'(x) = 0 ):

from sympy import symbols, solve

x = symbols('x')
f_prime = 4*x**3 + 6*x**2 - 22*x - 13
roots = solve(f_prime, x)
roots

The roots are:
[ p = -2 ]
[ q = 1 ]

Tangent Line Calculation

1. Slope at ( p ) and ( q ):
   [ f'(-2) = 4(-2)^3 + 6(-2)^2 - 22(-2) - 13 = -32 + 24 + 44 - 13 = 23 ]

2. Calculate ( f(p) ) and ( f(q) ):
   [ f(-2) = (-2)^4 + 2(-2)^3 - 11(-2)^2 - 13(-2) + 35 = 16 - 16 - 44 + 26 + 35 = 17 ]

[ f(1) = 1^4 + 2(1)^3 - 11(1)^2 - 13(1) + 35 = 1 + 2 - 11 - 13 + 35 = 14 ]

3. Equation of the tangent line:
   [ y - f(-2) = f'(-2)(x + 2) ]
   [ y - 17 = 23(x + 2) ]
   [ y = 23x + 46 + 17 ]
   [ y = 23x + 63 ]

Therefore, the equation of the tangent line is:
[ y = 23x + 63 ]

Ask chatgpt bro that shit knows everything

TH never lost sunset with wo0t