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most fair tokyo bracket

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#1
daystarky

i was wondering if this is really the best matchups possible and i decided to think in the "logic way" of seeding and regional distribution. i started with 4 pois:

pool 1: LOUD (AME#1), TL (EMEA#1), PRX (PAC#1)
pool 2: FNC (EMEA#2) (just a "extension" from pool 1)
pool 3: NRG (AME#2, A#1), EG (AME#3, B#1)
pool 4: EDG (CN#2 but only alive, A#2), DRX (PAC#2, B#2)

i follow this logic sequence:

  • teams from same group stay in the oppsite side (avoid same match twice at least until lower round 2)
  • Pool 3 or Pool 4 teams can not stay in the same side (seeding things)
  • 2 teams from Pool 1 take the 2 teams from Pool 4 (nothing new)
  • the last Pool 1 team and the Pool 2 team take the Pool 3 teams (again, nothing special)
  • teams from same regional league cannot stay in the same side or make a matchup unless if the only way possible (make regional matches most far away possible to happen)

this is the result:
TL or FNC x NRG
LOUD x DRX
FNC or TL x EG
PRX x EDG

the only real draw here is between FNC and TL and OF COURSE MAKE THIS IN LIVE

i can make most fair bracket from any global event if you want (only LOCK IN don't need, Riot actually made right)

TL:DR
Riot sucks in make "draws"

#2
aTastyCook1e
0
Frags
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PRX has to be pool 2 along with FNC, Pacific is a weak league.

#3
daystarky
0
Frags
+

i mean, Riot dont make a "regional strengh" yet this year, so i can't count this really

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